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question:a certain shopping mall, the turnover in April was 10 thousand yuan, and the turnover in May was 12 thousand yuan. If calculated with the same monthly growth rate, the turnover in June for the shopping mall would be ______ thousand yuan.
answer:To solve this problem, we first need to calculate the monthly growth rate from April to May. The growth rate can be calculated as the difference in turnover divided by the turnover at the beginning of the period. Then, we apply this growth rate to the turnover in May to find the turnover in June. The turnover in April was 10 thousand yuan, and in May it was 12 thousand yuan. So, the growth rate from April to May is calculated as follows: text{Growth Rate} = frac{text{Turnover in May} - text{Turnover in April}}{text{Turnover in April}} Substituting the given values: text{Growth Rate} = frac{12 - 10}{10} = frac{2}{10} = 0.2 This means the monthly growth rate is 20% or 0.2 in decimal form. To find the turnover in June, we apply this growth rate to the turnover in May. The formula to calculate the turnover in June, considering the same growth rate, is: text{Turnover in June} = text{Turnover in May} times left(1 + text{Growth Rate}right) Substituting the known values: text{Turnover in June} = 12 times left(1 + 0.2right) Simplifying the expression: text{Turnover in June} = 12 times 1.2 text{Turnover in June} = 14.4 Therefore, the turnover in June for the shopping mall would be boxed{14.4} thousand yuan.
question:cos20^circcos10^circsin160^circsin10^circ=(boxed{text{answer}}) A: frac { sqrt {3}}{2} B: frac { sqrt {3}}{2} C: frac {1}{2} D: frac {1}{2}
answer:**Analysis:** Directly utilize the induction formula and the trigonometric functions of the sum and difference of two angles to simplify and solve the problem. This problem tests the understanding of the trigonometric functions of the sum and difference of two angles, as well as the ability to simplify and calculate trigonometric functions. **Answer:** cos20^circcos10^circ-sin160^circsin10^circ=cos20^circcos10^circ-sin20^circsin10^circ=cos30^circ=boxed{frac{sqrt{3}}{2}} Therefore, the correct option is B.
question:the list 3, 3, 4, 4, 5, 5, 5, 5, 7, 11, 21, what is the mode of the data?
answer:The mode of a set of data is the number that appears most frequently. In the list provided, the number 5 appears four times, which is more than any other number. Therefore, the mode of the data is boxed{5} .
question:Round 2.0249 to the nearest hundredth using the rounding rule.
answer:Solution: Using the rounding rule, the approximate value of 2.0249 to the nearest hundredth is 2.02. Thus, the answer is: boxed{2.02}. This is achieved by rounding the digit in the thousandths place, which is 4 in this case. This problem tests the understanding of approximate numbers and significant figures. The closeness of an approximate number to an exact number can be represented by precision. It is generally expressed by saying to which place the number is rounded or how many significant figures are retained. All digits of a number from the first non-zero digit on the left to the last digit on the right are significant figures.